PyQt gui in maya 2011

[clapperboy]

Hello,
I wrote this simple interface using PyQt.

#!/usr/bin/python
 
import sys
from PyQt4 import QtGui
from PyQt4 import QtCore
 
class Test(QtGui.QWidget):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
#various window setting
        self.setGeometry(300, 300, 250, 150)
        self.setWindowTitle('Test')
        self.setWindowIcon(QtGui.QIcon('C:/Users/amenard/Desktop/icon.png'))
#create  ballon-style tooltip or window
        self.setToolTip('This is a <b>QWidget</b> widget.\nTake a look at the <i>icon</i> in the upper left corner.')
        QtGui.QToolTip.setFont(QtGui.QFont('OldEnglish', 10))#change the overall font on tooltip
#create a button to close down the gui
        cancel = QtGui.QPushButton('Cancel', self)#button widget
        cancel.setGeometry(10, 10, 60, 35)#place it
        cancel.setToolTip('This <b>button</b> will close down the window.')#set tool tip
#use QtCore module to close down the window       
        self.connect(cancel, QtCore.SIGNAL('clicked()'), QtGui.qApp, QtCore.SLOT('quit()'))
 
app = QtGui.QApplication(sys.argv)
aTest = Test()
aTest.show()
sys.exit(app.exec_())

 Now this runs fine outside maya.
But whn I tried to run this in maya 2011 through the script editor, it crashes the script editor returning this error:
# Error: SystemExit: file line 27: -1 #
 The gui opens though.
When I tried to re-open the script editor, I get this error
// Error: file: C:/Program Files/Autodesk/Maya2011/scripts/startup/scriptEditorPanel.mel line 1206: Object 'scriptEditorPanel1Window|TearOffPane|scriptEditorPanel1|formLayout37|formLayout39|paneLayout1|formLayout40|tabLayout2' not found.

 Any idea why that would work outside maya but not inside maya?

Thanks 

[joojaa]

Why on earth would you call sys exit inside a maya session?*

Anyway see the manual on how to pump the gui inside mayas pump having rest of the gui frozen is probably not your ballgame..

• what the hell are you thinking are you trying to make sure other maya users may not use python? It only makes sense to call sys.exit IF an only if the python is standalone.

PS: Did you just copy the code from a tutorial. As in general nobody comments stuff like that OTHER than in tutorials because its just plain wrong. NO point in commenting #set tooltip next to a .setTooltip method. defeats the netire point of commenting.

You comment when something is nonintuitive and even then you opt NOT to comment in favor of making the code read self explanatory. You also comment your methods and objects so that i dont have to read the code unless im interested in the internals of just said code. Se worst case is that the selexplanatory comment is still there after the self explanatory line is gone. Thats whan the WTF starts, i mean is ita  bug a residue or just plain wrong.

[clapperboy]

I'm a mel user that's moving into python.
only calling sys.exit because thats how I got it to work from a tutorial on pyqt.
I understood it's not a good usage inside maya since its returning an error on that specific line.

so I got rid of the lines refering to sys.

#!/usr/bin/python
from PyQt4 import QtGui
from PyQt4 import QtCore
 
class Test(QtGui.QWidget):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
#various window setting
        self.setGeometry(300, 300, 250, 150)
        self.setWindowTitle('Test')
        self.setWindowIcon(QtGui.QIcon('C:/Users/amenard/Desktop/icon.png'))
#create  ballon-style tooltip or window
        self.setToolTip('This is a <b>QWidget</b> widget.\nTake a look at the <i>icon</i> in the upper left corner.')
        QtGui.QToolTip.setFont(QtGui.QFont('OldEnglish', 10))#change the overall font on tooltip
#create a button to close down the gui
        cancel = QtGui.QPushButton('Cancel', self)#button widget
        cancel.setGeometry(10, 10, 60, 35)#place it
        cancel.setToolTip('This <b>button</b> will close down the window.')#set tool tip
#use QtCore module to close down the window       
        self.connect(cancel, QtCore.SIGNAL('clicked()'), QtGui.qApp, QtCore.SLOT('quit()'))
 
aTest = Test()
aTest.show()

 now the gui open without crashing the script editor.
but...
whn I push the button, it closes or crashes maya.
Is it because of the slot(quit()) ? That my guess, because whn I use slot(close()) it doesnt cloe maya.

[clapperboy]

got it

#!/usr/bin/python
from PyQt4 import QtGui
from PyQt4 import QtCore
 
class Test(QtGui.QWidget):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
#various window setting
        self.setGeometry(300, 300, 250, 150)
        self.setWindowTitle('Test')
        self.setWindowIcon(QtGui.QIcon('C:/Users/amenard/Desktop/icon.png'))
#create  ballon-style tooltip or window
        self.setToolTip('This is a <b>QWidget</b> widget.\nTake a look at the <i>icon</i> in the upper left corner.')
        QtGui.QToolTip.setFont(QtGui.QFont('OldEnglish', 10))#change the overall font on tooltip
#create a button to close down the gui
        cancel = QtGui.QPushButton('Cancel', self)#button widget
        cancel.setGeometry(10, 10, 60, 35)#place it
        cancel.setToolTip('This <b>button</b> will close down the window.')#set tool tip
#use QtCore module to close down the window       
        self.connect(cancel, QtCore.SIGNAL('clicked()'), self, QtCore.SLOT('close()'))
 
aTest = Test()
aTest.show()

 so I change the receiver from QtGui.qApp to self, and now it works fine.

any other comment on how the code is written to improve it?

Thanks 

[clapperboy]

Quick question about running this from a shelf and importing the script from the previous post.
Ill reprint it here just to avoid confusion

#!/usr/bin/python
from PyQt4 import QtGui
from PyQt4 import QtCore
 
class Test(QtGui.QWidget):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
#various window setting
        self.setGeometry(300, 300, 250, 150)
        self.setWindowTitle('Test')
        self.setWindowIcon(QtGui.QIcon('C:/Users/amenard/Desktop/icon.png'))
#create  ballon-style tooltip or window
        self.setToolTip('This is a <b>QWidget</b> widget.\nTake a look at the <i>icon</i> in the upper left corner.')
        QtGui.QToolTip.setFont(QtGui.QFont('OldEnglish', 10))#change the overall font on tooltip
#create a button to close down the gui
        cancel = QtGui.QPushButton('Cancel', self)#button widget
        cancel.setGeometry(10, 10, 60, 35)#place it
        cancel.setToolTip('This <b>button</b> will close down the window.')#set tool tip
#use QtCore module to close down the window       
        self.connect(cancel, QtCore.SIGNAL('clicked()'), self, QtCore.SLOT('close()'))
 
aTest = Test()
aTest.show()

This file is saved as pyQt_Basics_simpleGui_ma.py and is my PYTHON search path

I run this command from a shelf button(or from the script editor)

#!/usr/bin/python
import pyQt_Basics_simpleGui_ma
aTest= pyQt_Basics_simpleGui_ma.Test()
aTest.show

 Now this works fine when I click the shelf button the first time.
The gui opens, I can close it by using the button...
but whn I reclick the shelf button: nada, nothin happens...
Until i close maya, reopen it, and reclick the shelf button.

Any help?
Thanks 

[clapperboy]

this seems to work

#!/usr/bin/python
import pyQt_Basics_simpleGui_ma
reload(pyQt_Basics_simpleGui_ma)
aTest= pyQt_Basics_simpleGui_ma.Test()
aTest.show

 something I dont understand is when I get rid of the 2 last lines in pyQt_Basics_simpleGui_ma.py
aTest=Test()
aTest.show

and run the shelf button, it doesnt work anymore.
I thought when I import a py file, I could call up the class from that file.

 

[clapperboy]

got it.
turned out I was missing () at the end of aTest.show
here's my final script pyQt_Basics_simpleGui_ma.py

#!/usr/bin/python
from PyQt4 import QtGui
from PyQt4 import QtCore
 
class Test(QtGui.QWidget):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
#various window setting
        self.setGeometry(300, 300, 250, 150)
        self.setWindowTitle('Test')
        self.setWindowIcon(QtGui.QIcon('C:/Users/amenard/Desktop/icon.png'))
#create  ballon-style tooltip or window
        self.setToolTip('This is a <b>QWidget</b> widget.\nTake a look at the <i>icon</i> in the upper left corner.')
        QtGui.QToolTip.setFont(QtGui.QFont('OldEnglish', 10))#change the overall font on tooltip
#create a button to close down the gui
        cancel = QtGui.QPushButton('Cancel', self)#button widget
        cancel.setGeometry(10, 10, 60, 35)#place it
        cancel.setToolTip('This <b>button</b> will close down the window.')#set tool tip
#use QtCore module to close down the window       
        self.connect(cancel, QtCore.SIGNAL('clicked()'), self, QtCore.SLOT('close()'))

and my pyShelf button

#!/usr/bin/python
import pyQt_Basics_simpleGui_ma
aTest= pyQt_Basics_simpleGui_ma.Test()
aTest.show()

Hope my finding helps other beginners!
oh and sorry Joojaa for learning...

 

[joojaa]

Suggestion make init start the gui too. No real need to keep the gui object around is there?

Nothing wrong with learning,

PS style tip: Which im certainly bad at myself. Be consistent if you write first a = b then dont go a= b on one line and a=b on other and a =b on a third. Looks better and makes it easier to keep tidy later. (otherwise at 6 * 300 lines you give up)

[clapperboy]

mmm...i'm not grasping this suggestion entirely.
or I'm doing something wrong(most probably the latter)

I added self.show() at the end of my script to have __init__ start the gui

#!/usr/bin/python
from PyQt4 import QtGui
from PyQt4 import QtCore
 
class Test(QtGui.QWidget):
    def __init__(self, parent = None):
        QtGui.QWidget.__init__(self, parent)
#various window setting
        self.setGeometry(300, 300, 250, 150)
        self.setWindowTitle('Test')
        self.setWindowIcon(QtGui.QIcon('C:/Users/amenard/Desktop/icon.png'))
#create  ballon-style tooltip on window
        self.setToolTip('This is a <b>QWidget</b> widget.\nTake a look at the <i>icon</i> in the upper left corner.')
        QtGui.QToolTip.setFont(QtGui.QFont('OldEnglish', 10))#change the overall font on tooltip
#create a button to close down the gui
        cancel = QtGui.QPushButton('Cancel', self)#button widget
        cancel.setGeometry(10, 10, 60, 35)#place it
        cancel.setToolTip('This <b>button</b> will close down the window.')
#use QtCore module to close down the window       
        self.connect(cancel, QtCore.SIGNAL('clicked()'), self, QtCore.SLOT('close()'))
#have __init__ initialize the gui
        self.show()

 and then I tried to pop it open with this

import pyQt_Basics_simpleGui_ma
pyQt_Basics_simpleGui_ma.Test()

 which didnt work entirely, as I see the gui open and close in a fratcion of a second
now I called up the class by instancing it. 

import pyQt_Basics_simpleGui_ma
aTest = pyQt_Basics_simpleGui_ma.Test()

 now this works, but I think I should be able to call up the gui without instancing it?

that was your suggestion, wasn't it?
 

[joojaa]

which didnt work entirely, as I see the gui open and close in a fratcion of a second

yeah thats how python works. See you do not need to manage the memory, but you loose the ability to say when sometrhing is cleaned up. In this case since the object reference goes so goes the gui. So uness you signal that you want to keep a object then python clears it away as unused.

However you can keep it in a module level variable, thatway it will be stored for safekeeping untill the module gets unloaded